-3
30
let A = first card and let B = second card; then A = 3B and B = A-6; since A = 3B then B = (3B) - 6; solve B = 3 and A = 9
If b = 9 then the value of 10b is 90
a=7 b=9 ab=? ab is the multiplication of a & b there fore the value of ab=7*9=63
a = 6b = 9a + b = 6 + 9 = 15
-3
30
let A = first card and let B = second card; then A = 3B and B = A-6; since A = 3B then B = (3B) - 6; solve B = 3 and A = 9
Only when a and b have the same sign (or when a or b equals 0). Here are some examples: |2+4|=|2|+|4|--> |6|=|6|--> 6=6 TRUE |(-1)+(-3)|=|(-1)|+|(-3)|--> |(-4)|=1+3--> 4=4 TRUE |3+(-6)|=|3|+|(-6)|--> |(-3)|=3+6--> 3=9 FALSE
If b = 9 then the value of 10b is 90
a=7 b=9 ab=? ab is the multiplication of a & b there fore the value of ab=7*9=63
If a = 24 and b = 6, then a - b = 24 - 6 = 18
If a = 26 and b = 6 then a - b = 20.
If a + b = 6, what is the value of 3a + 3b?
If a = 24 and b = -6 then 24--6 = 30 because --6 = +6
If we know that two of the numbers are 6 and 9, and that these two might be one of the multiplied combinations mentioned, then the maximum possible value is 6 x 9 = 54.