This is a geometric series with common ratio 2.
The nth term is un = -3*2(n-1)
So u11 = -3*2(11-1) = -3*210 = -3*1024 = -3072
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To find the value of the nth term in an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference between terms. In this sequence, the first term (a_1 = 12) and the common difference (d = -6 - 0 = -6). So, the formula becomes (a_n = 12 + (n-1)(-6)). Simplifying this gives (a_n = 12 - 6n + 6). Therefore, the value of the nth term in this arithmetic sequence is (a_n = 18 - 6n).
12 - 5(n-1)
t(n) = 12*n + 5
The nth term of the sequence -4 4 12 20 29 is 8n+12 because each time the sequence is adding 8 which is where the 8n comes from. Then you take 8 away from -4 and because a - and - equal a + the answer is 12. Which is where the 12 comes from. Hope I helped.
The given sequence is an arithmetic sequence with a common difference of 7. To find the nth term of an arithmetic sequence, you can use the formula: nth term = first term + (n-1) * common difference. In this case, the first term is 12 and the common difference is 7. Therefore, the nth term of this sequence would be 12 + (n-1) * 7.