It is (-2)n-1 = (-2)10 = -1024
It is (-2)n-1 = (-2)10 = -1024
It is (-2)n-1 = (-2)10 = -1024
It is (-2)n-1 = (-2)10 = -1024
It is (-2)n-1 = (-2)10 = -1024
This is a geometric series with common ratio 2. The nth term is un = -3*2(n-1) So u11 = -3*2(11-1) = -3*210 = -3*1024 = -3072
The nth term is referring to any term in the arithmetic sequence. You would figure out the formula an = a1+(n-1)d-10where an is your y-value, a1 is your first term in a number sequence (your x-value), n is the term you're trying to find, and d is the amount you're increasing by.
0, 1, 1, 2, 3, 5, 8 so the 7th term is 8
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
The general term for the sequence 0, 1, 1, 2, 2, 3, 3 is infinite sequence.
1, 16, 81, 256 14641 is the 11th term.
x = 1
This is a geometric series with common ratio 2. The nth term is un = -3*2(n-1) So u11 = -3*2(11-1) = -3*210 = -3*1024 = -3072
The nth term is referring to any term in the arithmetic sequence. You would figure out the formula an = a1+(n-1)d-10where an is your y-value, a1 is your first term in a number sequence (your x-value), n is the term you're trying to find, and d is the amount you're increasing by.
0, 1, 1, 2, 3, 5, 8 so the 7th term is 8
To form a linear (or arithmetic) sequence you need two things: a starting value and the common difference. You have provided the common difference but not the starting value. If the starting value was a, then the nth term in the sequence would beT(n) = a + 5/4*(n - 1).
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
every next term is 4 smaller than previous so 7th term = -23
The general term for the sequence 0, 1, 1, 2, 2, 3, 3 is infinite sequence.
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
If the first two numbers are 0, 1 or -1 (not both zero) then you get an alternating Fibonacci sequence.
The nth term of the sequence is 2n + 1.