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You can find that by taking it's derivative and solving for zero. That will give you the x coordinate of the vertex, which you can then plug back in to find the y coordinate

y= x2 + x - 12

dy/dx = 2x + 1

Let dy/dx = 0:

0 = 2x + 1

x = -1/2

So:

y = (-1/2)2 - 1/2 - 12

= 1/4 - 2/4 - 48/4

= -49/4

So the vertex lies at the point (-1/2, -49/4)

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11y ago
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Q: What is the vertex Y equals x2 plus x-12?
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