The commutative property of multiplication states that the order of multiplication is unimportant. Because of this property x2 and 2x are the same. This allows us to rearrange the problem to become 2x + 2x + 1. In this expression we then combine the like terms with x's to become 4x + 1. At this point the expression is now simplified since we cannot combine the 4x and the 1 any further.
Answer: 4x + 1
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
(x + 3)(x - 1)
-x2 + 2x + 48 = (-x - 6)(x - 8)
2/x + 1/x2 = (2x+1)/x2
Factor x3 + x2 + 2x + 2, by grouping. Group the first two terms and the last two terms. Then factor. First, factor x3 + x2 by pulling out an x2 term: x2(x + 1) Second, factor 2x + 2 by pulling out a 2: 2(x + 1) So, you now have: x2(x + 1) + 2(x + 1) If you have factored correctly, the terms inside the parentheses should be the same. Now regroup. ANS: (x + 1)(x2 + 2)
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
y = x2 + 2x + 1zeros are:0 = x2 + 2x + 10 = (x + 1)(x + 1)0 = (x + 1)2x = -1So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
x2+2x+1 = (x+1)*(x+1)
3x2 + 2x + 3 + x2 + x + 1 = 4x 2+ 3x + 4
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
negative four: x2 - 2x + 5 = x2 - 2x + 5 - 4 = x2 - 2x + 1 = (x - 1)2
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
I'm answering this based on the way you wrote it. If you meant something different, please substitute words where necessary. x2-2x+4+2x+1-x62+5=2x-2x+4+2x+1-62x+5=-60x+10
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
It can be. x^2 + x + 1 is a factor of 2x^2 + 2x + 2
(x + 1)(x + 1)