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The expression xy + z represents the sum of the product of x and y with the value of z. This is a simple algebraic expression where x and y are variables representing numbers, and z is a constant value. To find the result of xy + z, you would first multiply x and y, and then add the value of z to the product.
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What is xy cubed z squared plus y squared z plus xyz completely factorised?
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
What is xy plus z equals 9 for y?
xy + z = 9Subtract 'z' from each side:xy = 9 - zDivide each side by 'x':y = (9 - z) / x
What is xy plus xy?
xy + xy = 2xy
If Z is the midpoint of XY then .?
Z is halfway between X and Y.
What are the factors of xy plus x plus y plus 1?
xy + x + y + 1 = (x + 1)(y + 1).
If xy plus y equals z then x equals?
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
What is xy cubed z squared plus y squared z plus xyz completely factorised?
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
How do you factor yz plus xy plus 4x plus 4z?
y(z+x) + 4(x+z)
What is xy plus z equals 9 for y?
xy + z = 9Subtract 'z' from each side:xy = 9 - zDivide each side by 'x':y = (9 - z) / x
Let xy x plus 2y and let xy x - z. Solve the following system of equations for x y and z (xy)z 4 x plus (x(y2))(-z) -2 (xy)(-z) 2?
To solve the system of equations given by ( xy = x + 2y ) and ( xy = x - z ), we can start by equating the two expressions for ( xy ). Setting ( x + 2y = x - z ) gives us ( 2y + z = 0 ) or ( z = -2y ). Substituting ( z ) into the other equation leads to a system that can be solved for ( x ) and ( y ). However, without numerical values or additional equations, we cannot find unique solutions for ( x, y, ) and ( z ).
If xz plus zy equals xy and xz equals zy then the point z is?
mid point of xy
If XZ plus ZY equals XY then point Z must be?
between X and Y
What is xy plus xy?
xy + xy = 2xy
What is lnx plus one half ln y minus 5ln z as a single logarithm?
lnx + .5lny - 5lnz First, make the coefficients into exponents: lnx + ln(y^.5) - ln(z^5) ln[xy^.5] - ln(z^5) ln[(xy^.5)/z^5] There you go!
What xy plus xy?
It is an expression in the form of: xy+7
If Z is the midpoint of XY then .?
Z is halfway between X and Y.
Prove that there do not exist real numbers x y and z such that x plus y plus z equals 0 and simultaneously 1 over x plus 1over y plus 1over z equals 0?
Suppose x + y + z = 0 then z = - x - y = -(x + y) . . . . . . (A) 1/x + 1/y + 1/z = 0 implies x, y and z are all non-zero: otherwise the reciprocals are undefined. then z ≠0 implies that x+y ≠0 (by (A)) so 1/x + 1/y + 1/[-(x+y)] = 0 (using (A)) so that 1/x + 1/y = 1/(x+y) ie (x + y)/xy = 1/(x + y) Now, since x+y ≠0, multiply both sides by x+y to give (x + y)2/xy = 1 or (x + y)2 = xy x2 + 2xy + y2 = xy x2 + xy + y2 = 0 so that x = [-y ± sqrt(y2 - 4y2)]/2 = [-y ± y*sqrt(-3)]/2 which is cannot be real if y is real.
