The ones digit is 5 less than 10 (10-5=5) The tens digit is 2 more than the ones digit (5+2=7) The entire number is less than 200. It could be either "75" or "175", but is probably "175" or they would have said that the entire number was less than 100.
The prime numbers between 25 and 50 are : 23 29 31 37 41 43 47However 2 and 4 (which appear in the tens place of 5 of these numbers) are not odd numbers.We are left with 31 and 37.The sum of digits of 37 is 10 which is not less than 10;but the sum of digits of 31 is 4 which is less than 10.So, 31 it is
According to the numerical puzzler, Digit total means adding up the digits in the number and then seeing if it is less than ten. Eg. 1111 = 1+1+1+1 = 4 and so is less than 10. 76 would be 7+6 = 13 and so would not be less than 10. Hope this helps?
The number that is 10 less than 5 is -5. When we subtract 10 from 5, we get -5. This is because subtracting a positive number (10) from a smaller number (5) results in a negative number.
To find a number that is 10 less than 305, you would subtract 10 from 305. So, 305 - 10 = 295. Therefore, the number that is 10 less than 305 is 295.
3
3
10 or 5
The ones digit is 5 less than 10 (10-5=5) The tens digit is 2 more than the ones digit (5+2=7) The entire number is less than 200. It could be either "75" or "175", but is probably "175" or they would have said that the entire number was less than 100.
The secret number must be a two-digit number greater than 25 and less than 50. Since the tens digit is odd, it can be 3, 5, or 7. However, the sum of the digits must be less than 10, so the only possible tens digit is 3. The units digit can be any number from 0 to 9 that, when added to 3, results in a sum less than 10. Therefore, the secret number is 31.
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
Meaningless question.
"The hundreds and the ones are the same digit and their sum is 10" did you say ?Well then, the hundreds and ones digit are both 5.And the tens is 2 less than that, or 3.So the number is . . . . . 535
There is an infinite number of values between 40 and 50, or between 4/10 and 5/10. Try 45 in the first case, and 9/20 in the second.
200 + 150 + 19 = 369
The prime numbers between 25 and 50 are : 23 29 31 37 41 43 47However 2 and 4 (which appear in the tens place of 5 of these numbers) are not odd numbers.We are left with 31 and 37.The sum of digits of 37 is 10 which is not less than 10;but the sum of digits of 31 is 4 which is less than 10.So, 31 it is
100 / 10 = 10.