Clearly we can't see the inequality here as the sign is missing, but if for example we have:
x2 < 25
then x < 251/2
The two square roots of 25 are 5 and -5.
Thus the values here will lie between the range -5 to 5 (exclusive - i.e. not including -5 and 5) which we can write as:
-5 < x < 5
An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.
that would be limited to 3 and -3 for values of x
if x2 ≠ 16, then: {x | x ∈ ℜ, x ∉ (4, -4)}
Id x2 = 169, then x = ±√169 = {-13, +13}
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10
x^2<25
x2 = 16take the root square for both sides the result will be :X = +4 or -4
x2≤64
x ≤ -sqrt(11) or x ≥ sqrt(11)
If x2 < 25 Then: |x| < 5 -5 < x < 5
An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.An inequality, like an equation, can have a different number of solutions depending on the inequality and the domain.For example, x2< 0 has no solutions if the domain is the real numbers.x< 5 has only one solution ( = 4) if the domain consists of the squares of positive even numbers.x < 5 has infinitely many solutions if the domain is the rational numbers or real numbers.
that would be limited to 3 and -3 for values of x
x2 - 25 = 0 is x2 = 25 thus x = 5 or x = -5, only 2 real solutions
Without further information, the only inequality is x2 ≥ 0 (assuming x is real). In the complex domain, there is no inequality.
Some symbols not visible. Please resubmit using words eg "plus", "equals" etc
The exact solutions are [5 ± sqrt(33)]/2. The approx values are -0.3723 and 5.3723
if x2 ≠ 16, then: {x | x ∈ ℜ, x ∉ (4, -4)}