4x - 2y = -6 4x - 4x - 2y = -4x - 6 - 2y = -4x - 6 divide by -2 to both sides y = 2x + 3 This is the equation of the line with slope 2, x-intercept -3/2 (y = 0), y intercept 3 (x = 0). By giving different values for x, we can find different values for y.
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation. But if you mean 4x+y = 10 then y = -4x+10 and the parallel equation is y = -4x+6
if your multiplying this numbers your going to need to compare the common variables. Y and Y. X and X. and also the ones with no variables. you do that and that's your answer. you can't solve it to get one number, your going to simplify it You would combine like terms. The like terms in this equation are x and 4x, 2y and 3y, and 0 and 15. You would then multiply each like term. x*4x=4x 2y*3y= 6y and 15*0=0. Your answer would then be 4x * 6y *0.
Parallel lines have the same slope. So if you put the equation 4x + y -1 = 0 into the slope-intercept form of the equation of a line (y = mx + b), you can read the slope, m, from it. Rearranging that equation gives: y = -4x + 1. The slope of both lines is -4. If the new line passes through the (x, y) point (1, 2), you can use the point-slope form of the equation of a line and plug in the values to find the equation of the new line: y - y1 = m(x - x1) y - 2 = -4(x - 1) y - 2 = -4x + 4 y = -4x + 6
4x - 2y = -6 4x - 4x - 2y = -4x - 6 - 2y = -4x - 6 divide by -2 to both sides y = 2x + 3 This is the equation of the line with slope 2, x-intercept -3/2 (y = 0), y intercept 3 (x = 0). By giving different values for x, we can find different values for y.
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
Let 4x + 2y = N Then 2y = -4x + N and, y = -2x + N/2 The y intercept occurs when x = 0 and so y = N/2
This line hits the x axis (y=0) when 4x + 0 = 4 (so x=1) and the y axis (x=0) at 0 + 2y = 4 (so y=2).
At the x-intercept, y=0 so...2y - 4x = -122(0) - 4x = -12-4x = -124x = 12x = 12/4x = 3
It is a straight line which goes through the points (2,0) and (0, -4)
x-2y+8 = 0 -2y = -x-8 y = 1/2x+4 in slope intercept form and the slope of the line parallel to it is 1/2
2y - 4x = -12 Algebraically rearrange to 2y = 4x - 12 Divide both sides by '2' y = 2x - 6 So at the 'y' intercept, x = 0 Substituting x = 0 We have y = 2(0) - 6 Anything multiplied '0' is equal; to '0' Hence y = 0 - 6 y = -6 is the value of the y-intercept.
Depending on what sign is supposed to appear before the 4, the x-intercept is either +3 or -3 .
2y-4x=-12 Add 4x to each side 2y=4x-12 Divide each side by 2 y=2x-6 The y-intercept is (0,-6)
4x + 2y = 12 3x - 2y = 9 Have to use simultaneous equations, so add together to get : 7x = 21 so x = 3 Put it into any part of the equation 4x3 + 2y = 12 12 + 2y = 12 2y = 0 y = 0, x = 3
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation. But if you mean 4x+y = 10 then y = -4x+10 and the parallel equation is y = -4x+6