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Call the two digit number xy. So: 10x + y = 2(x + y)

Multiplying out: 10x + y = 2x +2y

Rearranging: 8x = y We can at this point introduce the constraints that x and y must be integers between 0 and 9. Only one value of x will allow this: 1. So y = 8. The answer, then, is 18. Call the two digit number xy. So: 10x + y = 2(x + y)

Multiplying out: 10x + y = 2x +2y

Rearranging: 8x = y We can at this point introduce the constraints that x and y must be integers between 0 and 9. Only one value of x will allow this: 1. So y = 8. The answer, then, is 18.

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Q: Which number is equal to twice the sum of its two digits?
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