Call the two digit number xy. So: 10x + y = 2(x + y)
Multiplying out: 10x + y = 2x +2y
Rearranging: 8x = y We can at this point introduce the constraints that x and y must be integers between 0 and 9. Only one value of x will allow this: 1. So y = 8. The answer, then, is 18. Call the two digit number xy. So: 10x + y = 2(x + y)
Multiplying out: 10x + y = 2x +2y
Rearranging: 8x = y We can at this point introduce the constraints that x and y must be integers between 0 and 9. Only one value of x will allow this: 1. So y = 8. The answer, then, is 18.
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18 is the only number that matches these criteria.
The difference between a number x and twice y is equal to fifteen.
21
The Answer is 36 btw. 3 + 6 = 9 3 x 6 = 2(3x6) 2(18) = 36
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.