(x + 9)2 + (y + 12)2 = 36 (x + 16)2 + (y + 3)2 = 17
let the two circles with centre O and P are congruent circles, therefore their radius will be equal. given: AB and CD are the chords of the circles with centres O and P respectively. ∠AOB=∠CPD TPT: AB=CD proof: in the ΔAOB and ΔCPD AO=CP=r and OB=PD=r ∠AOB=∠CPD therefore by SAS congruency, ΔAOB and ΔCPD are congruent triangle. therefore AB=CD
Join the centre of the circle O and the point A .Extend it to both sides to form a line.This is the required locus
Circles with the same radius are congruent circles.
Concentric circles are circles with the same common centre.
When the centers of both the circles are at the same point.
Which point is not located on the xaxis or the yaxis of a coordinate grid?Read more:Which_point_is_not_located_on_the_xaxis_or_the_yaxis_of_a_coordinate_grid
They're circles that may have different sizes but their centers are at the same point.
They are the common tangents to the circles.
it intersects the segment joining the centers of two circles
A square does have a centre.
you draw a triangle formed by the centers of the two circles and use pythagoean theorem
It is called the ordinate.
clarify your question a bit man !
Yes, that is correct. Circles circumscribed about a given triangle will have centers that are equal to the incenter, which is the point where the angle bisectors of the triangle intersect. However, the radii of these circles can vary depending on the triangle's size and shape.
.... then your graph is inverted.
Yes, it does.