0
That is a quadratic equation and must be factorised using two brackets. It is just a little confusing to recognise it as a quadratic as the middle x value is not there so we treat it as 0 - which means the two numbers must cancel each other out:
(2x + 1) (2x - 1)
What else can I help you with?
How do you factor x squared minus 4x minus 5?
Find factors of -5 that can be added to make -4, in this case -5 and 1, so: (x - 5)(x + 1) = x2 - 4x - 5
Factor completely 8x squared plus 6x minus 5?
8x^2 + 6x - 5 = 8x^2 + 10x - 4x - 5 = 2x * (4x + 5) - (4x + 5) = (2x -1) * (4x + 5)
How do you factor 3x squared minus 8x minus 3?
(x-3)(3x+1)
Factor the polynomial 3x squared minus 14x minus 5?
(3x + 1)(x - 5)
What is the solution to 4x squared minus x minus 5 equals 0?
4x2 - x - 5 = 0 4x2 + 4x - 5x - 5 = 0 4x(x + 1) - 5(x + 1) = 0 (4x - 5)(x + 1) = 0 4x - 5 = 0 or x + 1 = 0 4x = 5 or x = -1 x = 5/4 o x = -1
How do you factor 8X squared minus 2X minus 1?
(2x - 1)(4x + 1)
How do you factor 4x squared minus 4x plus 1?
(2x-1)(2x-1) = 4x^2 -4x + 1
How do you factor 4x squared minus 1?
(2x - 1)(2x + 1)
How do you factor 4x squared minus 2x?
2x(2x - 1)
How do you factor 4x squared minus 4?
4(x - 1)(x + 1)
How do you factor 2x squared plus 4x minus 1?
There is no rational factorisation.
How do you factor 8 x squared minus ten x minus three?
8x2-10x-3 = (2x-3)(4x+1) when factored
Factor completely -use 2 methods- 4x squared plus 4x minus 8?
4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)
How do you factor x squared minus 4x minus 5?
Find factors of -5 that can be added to make -4, in this case -5 and 1, so: (x - 5)(x + 1) = x2 - 4x - 5
Factor completely 8x squared plus 6x minus 5?
8x^2 + 6x - 5 = 8x^2 + 10x - 4x - 5 = 2x * (4x + 5) - (4x + 5) = (2x -1) * (4x + 5)
How do you solve x squared minus 4x minus 5 equals 0?
X2 - 4X - 5 = 0 easy factor, what two factors of - 5 add up to - 4 (X + 1)(X - 5) X = - 1 ------------- X = 5 --------------
How do you factor A squared minus 1?
It is (A-1)(A+1) when factored
