0
That is a quadratic equation and must be factorised using two brackets. It is just a little confusing to recognise it as a quadratic as the middle x value is not there so we treat it as 0 - which means the two numbers must cancel each other out:
(2x + 1) (2x - 1)
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How do you factor x squared minus 4x minus 5?
Find factors of -5 that can be added to make -4, in this case -5 and 1, so: (x - 5)(x + 1) = x2 - 4x - 5
Factor completely 8x squared plus 6x minus 5?
8x^2 + 6x - 5 = 8x^2 + 10x - 4x - 5 = 2x * (4x + 5) - (4x + 5) = (2x -1) * (4x + 5)
How do you factor 3x squared minus 8x minus 3?
(x-3)(3x+1)
Factor the polynomial 3x squared minus 14x minus 5?
(3x + 1)(x - 5)
What is the solution to 4x squared minus x minus 5 equals 0?
4x2 - x - 5 = 0 4x2 + 4x - 5x - 5 = 0 4x(x + 1) - 5(x + 1) = 0 (4x - 5)(x + 1) = 0 4x - 5 = 0 or x + 1 = 0 4x = 5 or x = -1 x = 5/4 o x = -1
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