Well if your talking about H2O, it means there is 2 hydrogen molecules and one oxygen.
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Apply Pythagoras h^(2) = x^(2) + y(2) Hence for points ( -8,-3 ) & ( 4,5) h^(2) = (-8-4)^(2) + ( -3-5)^(2). h^(2) = (-12)^(2) + (-8)^(2) h^(2) = 144 + 64 h^(2) = 208 h = sqrt(208) h = 14.222051.... (The distance between the two points.
The answer is 30m. Lets assume that the ball is dropped from a height of h. The ball will come down and go up, so in the first bounce it covers h+h/2 distance. The second bounce, it is h/2+h/4, the third it will be h/4+h/8 and so on. The total distance covered would thus be h+h/2+h/2+h/4+h/4+h/8+h/8+........... = h+h+h/2+h/4+h/8+........... (summing up adjacent values in pairs) = 2h+h*(1/2+1/4+1/8+.............) = 3h (by the geometric series formula, 1/2+1/4+1/8+.....=1) Hence taking, h=10m in this case, the answer would be 10*3= 30m
Each flip can land in 2 ways. Total number of possible ways that 5 flips can land is2 x 2 x 2 x 2 x 2 = 32 different ways.There are only 5 different ways to get exactly 3 heads in a row in 5 flips.They are:H H H T TH H H T HT H H H TT T H H HH T H H H.The probabilty is 5/32 = 15.625 percent.====================================================That's if you mean exactly 3 heads in a row ... no less and no more.What if you asked for "at least 3 heads in a row" ?There are 8 ways to do that:The original five ways to get 3 in a row . . .H H H T TH H H T HT H H H TT T H H HH T H H HPlus 2 ways to get 4 in a row . . .T H H H HH H H H TPlus a way to get 5 in a row . . .H H H H H.The probability of one of these outcomes is 8/32 = 25 percent.
A = (bh)/2 = [(4h - 2)h]/2 = (2h - 1)h = 22h - h Restriction: 2h - 1 > 0 implies h > 1/2, since the area cannot be zero or negative.