Restricting the argument of a complex number between -π and π is a common practice because it allows for a unique representation of the number in polar form. This range ensures that the principal argument lies within one full rotation in the complex plane, simplifying calculations involving angles and trigonometric functions. Additionally, it helps avoid ambiguity and ensures consistency in mathematical operations involving complex numbers.
Oh, dude, it's like when you're dealing with complex numbers, you gotta keep them in check, you know? So, by restricting the argument between -pi and pi, you're basically just making sure your complex number stays in line and doesn't go off causing trouble in the mathematical neighborhood. It's like giving them a curfew to prevent any wild imaginary escapades.
A complex number (z = x + iy) can be plotted the x-y plane if we consider the complex number the point (x,y) (where x is the real part, and y is the imaginary part). So once you plot the complex number on the x-y plane, draw a line from the point to the origin. The Principle Argument of z (denoted by Arg z) is the measure of the angle from the x-axis to the line (made from connecting the point to (0,0)) in the interval (-pi, pi]. The difference between the arg z and Arg z is that arg z is an countably infinite set. And the Arg z is an element of arg z. Why? : The principle argument is needed to change a complex number in to polar representation. Polar representation makes multiplication of complex numbers very easy. z^2 is pretty simple: just multiply out (x+iy)(x+iy). But what about z^100? This is were polar represenation helps us, and to get into this representation we need the principle argument. I hope that helped.
The square root of a positive real number can either be +/-. The principle square root is defined as the positive value. sqrt(9) is +/- 3, but the principle square root of 9 is 3. For complex numbers the principle square root is the argument (or angle) of the complex number that lies between (-pi,pi]. I am pretty sure that the upper angle pi is closed while the lower angle -pi is open, but not 100%.
Adjoint operator of a complex number?
No. It is an imaginary (or complex) number.
There is no such number. If you restrict yourself to integers, there are numbers - such as primes, that are not divisible by an integer other than one. And if you do not restrict yourself to intgers, then there is no smallest number sincce given any number, half that number will be smaller and will be a divisor.
PRINCIPAL ARGUMENT = ARGUMENT + 2nPI arg(Z) = Arg (Z) + 2nPI
Argument Hopes this help!!
This is best done if the complex number is in polar coordinates - that is, a distance from the origin, and an angle. Take the square root of the argument (the absolute value) of the complex number; and half the angle.
arg(-2-i) = sqrt[22 + 12] = sqrt(5)
False apex
A complex number (z = x + iy) can be plotted the x-y plane if we consider the complex number the point (x,y) (where x is the real part, and y is the imaginary part). So once you plot the complex number on the x-y plane, draw a line from the point to the origin. The Principle Argument of z (denoted by Arg z) is the measure of the angle from the x-axis to the line (made from connecting the point to (0,0)) in the interval (-pi, pi]. The difference between the arg z and Arg z is that arg z is an countably infinite set. And the Arg z is an element of arg z. Why? : The principle argument is needed to change a complex number in to polar representation. Polar representation makes multiplication of complex numbers very easy. z^2 is pretty simple: just multiply out (x+iy)(x+iy). But what about z^100? This is were polar represenation helps us, and to get into this representation we need the principle argument. I hope that helped.
When a complex number is multiplied by its conjugate, the product is a real number and the imaginary number disappears.
Graphically, the conjugate of a complex number is its reflection on the real axis.
In the complex field, the two numbers are the same. If you restrict yourself to real solutions, the relationship is as follows: A polynomial of degree p has p-2k real solutions where k is an integer such that p-2k is non-negative. [There will be 2k pairs of complex conjugate roots.]
yes
If you add two complex numbers, the resulting complex number is equivalent to the vector resulting from adding the two vectors. If you multiply two complex numbers, the resulting complex number is equivalent to the vector resulting from the cross product of the two vectors.
No difference. The set of complex numbers includes the set of imaginary numbers.