0
If y = sin x:
x can take on any value, so the domain is the set of real numbers.
y can take on values between -1 and 1 (including the extremes); so the range is -1 <= y <= 1.
If y = sin x:
x can take on any value, so the domain is the set of real numbers.
y can take on values between -1 and 1 (including the extremes); so the range is -1 <= y <= 1.
If y = sin x:
x can take on any value, so the domain is the set of real numbers.
y can take on values between -1 and 1 (including the extremes); so the range is -1 <= y <= 1.
If y = sin x:
x can take on any value, so the domain is the set of real numbers.
y can take on values between -1 and 1 (including the extremes); so the range is -1 <= y <= 1.
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What jobs use domains and range and how do they use it?
Domains and ranges are commonly used in fields such as mathematics, computer science, economics, physics, and engineering. In mathematics, domains and ranges help define the inputs and outputs of functions, which are essential for solving equations and analyzing data. In computer science, domains and ranges are used in programming to determine the scope and limits of variables and functions. In economics, domains and ranges help model relationships between variables in economic systems. In physics and engineering, domains and ranges are crucial for understanding the behavior of physical systems and designing solutions based on specific input-output relationships.
Prove this identity 1 plus cosx divide by sinx equals sinx divide by 1-cosx?
2
How do you solve 1 minus cosx divided by sinx plus sinx divided by 1 minus cosx to get 2cscx?
(1-cosx)/sinx + sinx/(1- cosx) = [(1 - cosx)*(1 - cosx) + sinx*sinx]/[sinx*(1-cosx)] = [1 - 2cosx + cos2x + sin2x]/[sinx*(1-cosx)] = [2 - 2cosx]/[sinx*(1-cosx)] = [2*(1-cosx)]/[sinx*(1-cosx)] = 2/sinx = 2cosecx
How do you verify the identity sinx cscx 1?
sinx cscx = 1 is the same thing as sinx(1/sinx) = 1 which is the same as sinx/sinx = 1. This evaluates to 1=1, which is true.
Can you Show 1 over sinx cosx - cosx over sinx equals tanx?
From the Pythagorean identity, sin2x = 1-cos2x. LHS = 1/(sinx cosx) - cosx/sinx LHS = 1/(sinx cosx) - (cosx/sinx)(cosx/cosx) LHS = 1/(sinx cosx) - cos2x/(sinx cosx) LHS = (1- cos2x)/(sinx cosx) LHS = sin2x /(sinx cosx) [from Pythagorean identity] LHS = sin2x /(sinx cosx) LHS = sinx/cosx LHS = tanx [by definition] RHS = tanx LHS = RHS and so the identity is proven. Q.E.D.
