26
It is 9.
The distance is 5. The x distance is 3, the y distance is 4, and the diagonal issqrt(32 + 42) = sqrt (9 + 16) = sqrt 25 = 5
The distance is about 7.62 (units).sqrt (9 + 49) = sqrt 58 = 7.61577
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
Points: (23, -33) and (4, 9) Distance: square root of 2125 which is about 46
9
The distance is 15, because -6 is 6 spaces away from zero and 9 is 9 spaces away from zero. You add the two distances to find the distance between the two numbers.
26
It is 9.
The distance is 5. The x distance is 3, the y distance is 4, and the diagonal issqrt(32 + 42) = sqrt (9 + 16) = sqrt 25 = 5
9
10
If the points are (3, 2) and (9, 10) then the distance works out as 10
The distance between the start point and the destination is 582 miles, and will take approximately 9 hours 32 minutes of driving time.
The distance is about 7.62 (units).sqrt (9 + 49) = sqrt 58 = 7.61577
The distance between the start point and the destination is 466 miles, and will take approximately 7 hours 9 minutes of driving time.