3
y=x^2
Flipping the graph of the function ( y = x^2 + 2x - 2 ) vertically involves multiplying the entire function by -1. This results in the new equation ( y = -(x^2 + 2x - 2) ), which can be simplified to ( y = -x^2 - 2x + 2 ). So, yes, the flipped graph can be represented as ( y = -(x^2 + 2x - 2) ).
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
No, but any parabola can be transformed into the form y = x^2.
If you mean: y = x^2 -6x +6 then the vertex is at (3, -3)
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10
If you're looking to factor it, you can do it like so: d2ydx2 - yx2 = d3yx2 - yx2 = yx2(d3 - 1)
y=x^2
Flipping the graph of the function ( y = x^2 + 2x - 2 ) vertically involves multiplying the entire function by -1. This results in the new equation ( y = -(x^2 + 2x - 2) ), which can be simplified to ( y = -x^2 - 2x + 2 ). So, yes, the flipped graph can be represented as ( y = -(x^2 + 2x - 2) ).
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
upward
There can be no answer because there is no equation of inequality, simply an expression.
y - x = 2 y= -2x + 1
12 x 5 = 60
y=x2-6x+9
No, but any parabola can be transformed into the form y = x^2.