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No. An expression such as b2 -16 does not normally have a distance associated with it.
It cannot factor without imaginary numbers
l a2 b2 is c2!!Its completely norma
as a2+b2=(a+ib)(a-ib), b2+2=[b - i sqrt(2)] [b + i sqrt(2)]
9a4-b2=36a-2b=2(18-b) But if you meant 9a^4-b^2 it is not possible to factor
Assuming the exponential form, 9a4 - b2 has the factors (3a + b)(3a - b).
b(b - 8)
(a - b + 2)(a + b + 2)
4a2 + 4ab - y2 + b2 You cannot simplify this expression because it does not contain like terms, but you can factor it such as: 4a2 + 4ab - y2 + b2 = (4a2 + 4ab + b2) - y2 = (2a + b)2 - y2 = [(2a + b) - y][(2a + b) + y]
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No. An expression such as b2 -16 does not normally have a distance associated with it.
b2-4ac
a2-b2 = (a-b)(a+b)
x2 - 4 is a special expression that is referred to as a difference of squares. Whenever an expression is in the format: a2 - b2 it can be factored out as: (a + b)(a - b) In the case of x2 + 4, that would be: (x + 2)(x - 2)
(a + b)(a - b)
b2(9b-8)