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The quartic polynomial that seems to be given has no rational factors: even if the first term were x^2 or the second 16x^2.
It is: 1(x4+4y8) and can't be factored any further
(x - 1)(x + 1)(x2 + 1)
18xy is the GCF of 72x2y and 18xy
(x+2)6 (x2 + 4x + 4)(x+2)4 (x2 + 4x + 4)(x2 + 4x + 4)(x+2)2 (x2 + 4x + 4)(x2 + 4x + 4)(x2 + 4x + 4) (x4 + 4x3 + 4x2 + 4x3 + 16x2 + 16x + 4x2 + 16x + 16)(x2 + 4x + 4) (x4 + 8x3 + 24x2 + 32x + 16)(x2 + 4x + 4) (x6 + 4x5 + 4x4 + 8x5 + 32x4 + 32x3 + 24x4 + 96x3 + 96x2 + 32x3 + 128x2 +128x + 16x2 + 64x + 64) (x6 + 12x5 + 60x4 + 160x3 + 240x2 + 192x +64) the coefficeints are 1, 12, 60, 160, 240, and 192
x6 - 27 = (x2 - 3)*(x4 + 3x2 + 9) Danny rocks
(x - 2)(x + 2)(x - 3)(x + 3)
Limx→0 [ 1 / (x - 4) + 1 / (x + 4) ] / x = Limx→0 1 / (x2 - 4x) + 1 / (x2 + 4x) = Limx→0 (x2 + 4x) / (x4 - 16x2) + (x2 - 4x) / (x4 - 16x2) = Limx→0 (x2 + 4x - 4x + x2) / (x4 - 16x2) = Limx→0 2x2 / (x4 - 16x2) = Limx→0 2 / (x2 - 16) = 2 / (0 - 16) = -1/8
It is: 1(x4+4y8) and can't be factored any further
-32
x5 - 1024 = (x - 4)(x4 + 4x3 + 16x2 + 64x + 256)
x4 - 4x3 - 12x2 -32x + 64 (x - 4)(x + 2)(x + 2)(x - 4)
If there is a remainder then it's not a factor otherwise yes
(x - 1)(x - 4)(x + 1)(x + 4)
x(x4+x3+x2+x+1)
(x4 - 3)(x4 + 3)
9 x 4 = 36
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4