n^2 + 5n = 0Where there is no constant term, then there is one monomial and one binomial factors. In this case the monomial is n and the binomial is (n + 5)
So n*(n + 5) = 0 which leads to the solutions n = 0 or n = 5.
h = +11 and/or -11
a2 + 2a - 3 = 0(a + 3)(a - 1)a = - 3a = 1Simple factoring where you ask yourself; what two factors of - 3 add up to 2?
Solve using the quadratic formula
If x squared -10 = 0 then x = the square root of 10
(x-5)(x+3)
By factoring. q2 + 16q = 0 q (q + 16) = 0 Now, either q = 0, or q + 16 = 0. Solve those two equations to get the solution.
Solve this problem -x squared -40x- 80 =0
5.
If r-squared = theta then r = ±sqrt(theta)
root 7
h = +11 and/or -11
a2 + 2a - 3 = 0(a + 3)(a - 1)a = - 3a = 1Simple factoring where you ask yourself; what two factors of - 3 add up to 2?
Solve using the quadratic formula
If x squared -10 = 0 then x = the square root of 10
(x-5)(x+3)
(x-3)(x-2)
X=1