There are 24 combinations using each digit once per combination: 1234 1243 1324 1342 1423 1432 2134 2143 2314 2341 2413 2431 3124 3142 3214 3241 3412 3421 4123 4132 4213 4231 4312 and 4321.
I am 11 and I tried this for fun.
I found 287 combinations.
Now I am working on 9 digit with numbers 1 - 9.
Wish me luck...
You would get 4!/2! = 12 combinations.
There are 5,040 combinations.
With 4 digits you can have 24 = 16 combinations. 1 combination with 0 digits; 4 combinations with 1 digit: 1, 2, 4 and 8 6 combinations with 2 digits: 12, 14, 18, 24, 28 and 48 4 combinations with 3 digits: 124, 128, 148 and 248 1 combination with all 4 digits. In a combination the order of digits is not relevant so that 124 is the same as 142.
I can't
how many combinations of 4 numbers are there in 7 numbers
There are 840 4-digit combinations without repeating any digit in the combinations.
There are 210 4 digit combinations and 5040 different 4 digit codes.
You would get 4!/2! = 12 combinations.
216
There are 5,040 combinations.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
There would be 9*9*9*9 or 6561 combinations.
1296 or (6^4)
4+4+4+4+4= 20
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
If the 6 digits can be repeated, there are 1296 different combinations. If you cannot repeat digits in the combination there are 360 different combinations. * * * * * No. That is the number of PERMUTATIONS, not COMBINATIONS. If you have 6 different digits, you can make only 15 4-digit combinations from them.
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