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Assuming no repeated digits, 720; allowing repeats 66 ie 46656.

* * * * *

No, 720 is the number of permutations! In a combination, the order does not matter. So without repeats, there are 2n-1 = 63 combinations.

Of these, 1 will consist of all 6 digits

6 will consist of 5 digits

15 will consist of 4 digits

20 will consist of 3 digits

15 will consist of 2 digits

6 will consist of 1 digit.

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Q: How many number combinations can you make out of the numbers 1-6?
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