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Assuming no repeated digits, 720; allowing repeats 66 ie 46656.
* * * * *
No, 720 is the number of permutations! In a combination, the order does not matter. So without repeats, there are 2n-1 = 63 combinations.
Of these, 1 will consist of all 6 digits
6 will consist of 5 digits
15 will consist of 4 digits
20 will consist of 3 digits
15 will consist of 2 digits
6 will consist of 1 digit.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
9000
35
None. You do not have enough numbers to make even one combination.
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.