No. It doesn't end in a 5 or 0.
There is no 5 digit number which is divisible by 23456910 (an 8-digit number)..
No. 35 is divisible by: 1, 5, 7, 35.
40 is divisible by 1, 2, 4, 5, 8, 10, 20 and 40.
No. But 870 is divisible by 3 (because 8+7+0 = 15 -> 1 + 5 = 6 and 6 is divisible by 3). 870/3 = 290.
3805 is divisible by 5 evenly whereas 3805 is not divisible by 8 evenly
760 is evenly divisible by both 5 and 8
3*8*5=120, therefore 120 is divisible by 3, 8 and 5.
42 is divisible by 14, but not divisible by 8, 5 nor 9.
280/5 = 56 280/8 = 35 Therefore, 280 is divisible by both 5 and 8.
if Divisible by 5 = ends in 0 or 5 if Palindrome = spelled the same forwards as backwards then number begins and ends with either 0 or 5 5_5, or 0_0 Sum is divisible by 8 5+5=10 16=divisible by 8 565
To be divisible by 36 the number must be divisible by 9 (and 4). To be divisible by 9, the sum of the digits must be divisible by 9. 5 + 5 = 10 → need an extra 8 → A + B = 8.
For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.
840 is the smallest number that is divisible by 5 6 7 and 8.
No, it does not go in evenly. To be divisible by 8 it would need to be divisible by two and 5 being and odd number is not.
Yes. The answer is 5.
40