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√(x-3) = x-5
x-3 = (x-5)2
x-3 = x2 -10x+25
0=x2-11x+28
0=(x-7)(x-4)
x-7=0, x-4=0
x=7, x=4
Check:
√(7-3) = 7-5
√4 = 2
2=2
yes
√(4-3) = 4-5
√1 = -1
no
Take the square root of both sides of the equation
What square root property is essential to solve any radical equation involving square root?
The answer will depend on how far the square root sign goes.If you want to solve for "x", I suggest you isolate the square root on the left (if it only covers the "2x" part, move the "1" to the other side of the equation). Then, if you square both sides of the equation, you get a formula which you can easily convert to a form which can be solved with the quadratic equation.
87
To solve this problem, you must first solve the smaller problems. The square root of 25 is 5, and the square root of 120 is 10.95. First solve the equation on the left side of the multiplication sign, which is 4 x 5. Now, multiple the answer of 20 by 10.95, which is 219.