1st term= 3 2nd term = 5 Nth term = 2n+1 10th term= 21 = 2(10)+1
The nth term of the sequence is 2n + 1.
Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.
5
n = 1, 2n = 2 n = 2, 2n = 4 n = 3, 2n = 6 2, 4, 6, ..., 2n where n = 1, 2, 3, ... This is an arithmetic sequence, where the first term is 2 and the common difference is 2.
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
2n(n+1)
2n(n+1)
(1/2n-r)2+((n2+2n)/4) where n is the row number and r is the position of the term in the sequence
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)
2n-1 to the tenth term = 1
work it out it's one more than the 8th and one less than the 10th * * * * * The above answer seems to make no sense here. It is not clear what you mean by a fraction sequence. It is not possible to go through the process for finding the nth term in an arithmetic, geometric or power sequence here. For school mathematics, sequences of fractions are, in fact composed of two simple sequences. One sequence defines the numerators and the other defines the denominators. In such cases, the nth term of the fraction sequence is the fraction given by the nth term of the numerator sequence divided by the nth term of the denominator sequence. For example: 1/1, 3/4, 5/9, 7/16, 9/25, ... The numerators are the odd number, with t(n) = 2n-1 The denominators are the squares of natural numbers with u(n) = n2 So, the nth term of the fraction sequence is (2n-1)/n2.