answersLogoWhite

0


Best Answer

An example of five even integers starting with -6 are -68, -66, -64, -62 and -60.

or

-6, -4, -2, 0, 2

or

-6, -8, -10, -12, -14

User Avatar

Wiki User

7y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

8y ago

-6, -4, -2, 0, 2

-6, -8, -10, -12, -14

This answer is:
User Avatar

User Avatar

Wiki User

8y ago

Start with -6. Add 2. Add another 2 : do that 4 times.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What are five even consecutive integers starting with -6?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Five consecutive integers starting with 6?

-6, -5, -4, -3 and -2.


What are five consecutive even integers starting at negative six?

-6, -4, -2, 0, 2 -6, -8, -10, -12, -14


What are Five consecutive even integers starting with negative six?

-6, -4, -2, 0, 2 or -6, -8, -10, -12, -14


What are the Five consecutive odd integers starting with negative three?

-3, -1, 1, 3, 5


Name five consecutive odd integers starting with -3?

-3, -5, -7, -9, -11


Five times the smallest of three consecutive even integers is 10 more than twice the largest. find the integers?

5872345098234783904672083946728390752430689723409687298290843 theres your answer


What is the sum of four consecutive even integers is 2 more than five times the first integer?

The integers would begin with 10.


If five consecutive numbers have a sum of 360 what is the value of the greatest integer?

The value of the greatest integer is 76. This occurs when the set of five consecutive integers is all even numbers.


What is a set of five consecutive integers that are all composite?

4,6,8,9,10


The sum of ten consecutive integers is five what is the largest of these integers?

The integers are -4, -3, -2, -1, 0, 1, 2, 3, 4 and 5. The largest is five.


Five times the first of three consecutive even integers is 14 more then 3 times the second?

Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.


When the smaller of two consecutive integers is added to five times the larger the result is 65?

The integers are 10 and 11.