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Q: What is 3a plus 4 plus b plus 2a plus 5 plus b?

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If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1

5a + 11

5a - 5 = 7 + 2a ( subtract 2a from both sides) 3a - 5 = 7 (add 5 to both sides) 3a = 12 ( divide both sides by 3) a = 4

3a + 4b - 5 - 1a + 7b + 3 - 1b 2a + 10b - 5 + 3 2a + 10b - 2

(6a3 - 19a2 + 15a)/(2a - 3) = a(6a2 - 19a + 15)/(2a - 3) = a(2a - 3)(3a -5)/(2a -3) = a(3a - 5)

depends what 'a' =

2a + 4b - 52a + 4b - 52a + 4b - 52a + 4b - 5

(3a+4)/12 - (5/3) = (2a-1)/2Multiply each side by 12:(3a+4) - (20) = 6 (2a-1)Eliminate the parentheses:3a + 4 - 20 = 12a -63a -16 = 12a -6Add 6 to each side:3a -10 = 12aSubtract 3a from each side:-10 = 9aDivide each side by 9:-10/9 = a

-2a + 5 = 1 -2a = -5 + 1 -2a = -4 a = -4/-2 a = 2

2a-5=-3a5a-5=05a=5a=0

The problem 3a-1 and 2a-5 is greater by 7. This is a math problem.

3a + a = 4a Example: a = 5 (3x5) + 5 = 15 + 5 = 20 = 4 x 5

= 3 X 2 = 6 = a X a = a2 (a square) = 6a2 + 5 Answer

a is equal to 4

15a - 25b + 20 = 5 (3a - 5b + 4)

6a-3

12(8a + 28) + 2a + 5 84a + 336 + 2a + 5 86a + 341

2a + 7b = -13a - 7b = -5The system of equations can be solved by elimination:2a + 3a = -65a = -6a = -6/5substitute the value of a in any of the two original equations to find the value of b:2(-6/5) + 7b = -1-12/5 + 1 = -7b-7/5 = -7bb= 1/5

2a-3+4b-2a-b-3+5=3b-1

-2

5(3a - 5b + 4)

2a-3+4b-2a-b-2a-b-3+5 Can be simplified to: 3b-1

9a +8 -2a -3 -5a = 2a +5

3a=3xa and if a = 5 it would be 3x5 which = 15 2b=2xb and if b = 2 it would be 2x2 which = 4 15+4=19

To my opinion and search, I believe that 3a+5 can be written as 3/5 a