y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
y-3x-3 y=3x+3 A line with a slope of 3 crossing the y-axis at 3.
Slope=3, y-intercept=0. y=3x or y=3x+0
y = 3x-1 The y intercept is -1 y = 3x-11 The y intercept is -11
3x - y = -4 3x - y = 0 Those lines do not intersect. They are parallel. You can demonstrate by solving either of them for one of the two variables, then plugging it's value into the other: 3x - y = -4 ∴y = 3x + 4 Now substitute: 3x - y = 0 ∴ 3x - (3x + 4) = 0 ∴ 3x - 3x - 4 = 0 ∴ -4 = 0 This result is obviously incorrect, indicating that the lines do not intersect.
3x - y = 4 Get y by itself to see if it is the same as y = 3x - 4: 3x = 4 + y 3x - 4 = y Therefore, 3x - y = 4 is the equivalent of y = 3x - 4.
-9
your equation is y=3x + 4 here are five parallel equations... y=3x + 5 y=3x + 6 y=3x + 7 y=3x + 8 y=3x + 9
y = 3x + 1 y = 3x + 2 y = 3x + 3 y = 3x
3x-y=9 y=3x-9
3x - y = 12 is the same as 3x - 12 = y, or y = 3x - 12.
y = 2 sin 3x y' = 2(sin 3x)'(3x)' y' = 2(cos 3x)(3) y' = 6 cos 3x
y = 3x 3x + 4y = 30 3x + 4(3x) = 30 3x + 12x = 30 15x = 30 x = 2 y = 3x y = 3(2) y = 6 (2, 6)
-2
y-3x-3 y=3x+3 A line with a slope of 3 crossing the y-axis at 3.
3x-y to the third becomes (x+x)+x-y*y*y the question is (3x-y)3
y = 3x - 2 3x = y + 2 x = y + 2 --------- 3