10
8-bit 2s complement representation of -19 is 11101101 For 1s complement invert all the bits. For 2s complement add 1 to the 1s complement: With 8-bits: 19 � 0001 0011 1s � 1110 1100 2s � 1110 1100 + 1 = 1110 1101
87
The largest 8-bit negative number that can be represented using two's complement is -1. In two's complement representation, -1 is expressed as 11111111 in binary. This is because the most significant bit (MSB) indicates the sign, and in this case, it is set to 1, indicating a negative number. The range of 8-bit two's complement numbers is from -128 to 127.
1
Using 4 bits the signed range of numbers is -8 to 7. When working with signed numbers one bit is the sign bit, thus with 4 bits this leaves 3 bits for the value. With 3 bits there are 8 possible values, which when using 2s complement have ranges: for non-negative numbers these are 0 to 7; for negative numbers these are -1 to -8. Thus the range for signed 4 bit numbers is -8 to 7.
-15 is 11111111 and 2s com is 1111 0001
Angle + Its Complement = 90 degrees Angle = Its Complement + 8 degrees2*(Its Complement) + 8 degrees = 90 degrees2*(Its Complement) = 82 degreesIts Complement = 41 degreesAngle + 41 degrees = 90 degreesAngle = 49 degrees
There are 8 atoms of hydrogen present in NH4 2S. This is because there are 4 hydrogen atoms in each ammonium ion (NH4+) and there are 2 ammonium ions in NH4 2S.
If you mean: -4+3+2s = 15 then s = 8
6s+2s=72 combine like terms 6s+2s=8s set equal to 72 8s=72 divide both sides by 8 to solve for "s". 8s=72 8 8 your answer is s= 72/8 which is 9.
Four 2s make 8, so 25% is your answer
You can detect overflow if the result turns out to be negative (which is the same as checking to see if the sign bit is 1). For example if you tried to add 5 and 6 in to 4-bit 2s complement, you would get 0101 + 0110 = 1011, which is a negative number since the sign bit (the 1 on the left) is a 1. This is an overflow.