1
To combine the expressions (-4x + 3y + x) and (-2z + 2y), first simplify the first expression by combining like terms: (-4x + x = -3x), so it becomes (-3x + 3y). Now, add the second expression: (-3x + 3y - 2z + 2y). Combining the (y) terms gives you (-3x + 5y - 2z). The final result is (-3x + 5y - 2z).
3xz
-2z + 3
To solve the expression ((m \times 2z) - (x - y)), first simplify the terms. Multiply (m) by (2z) to get (2mz). Then, distribute the negative sign in the second part: (-x + y). The final expression combines these results: (2mz - x + y).
2z-28 = -26
The GCF is 2z
2z(5z - 1)(25z^2 + 5z + 1)
(-3) x (-2z - 7) = 6z + 21 = 3 (2z + 7)
3xz
-2z + 3
To solve the expression ((m \times 2z) - (x - y)), first simplify the terms. Multiply (m) by (2z) to get (2mz). Then, distribute the negative sign in the second part: (-x + y). The final expression combines these results: (2mz - x + y).
2z-28 = -26
(x+y)^2+z^2=x^2+y^2+z^2+2xy or ((x+y)^2+z)^2= (x^2+y^2+2xy+z)^2= x^4+y^4+z^2+6x^2y^2+4x^3y+2x^2z^2+4xy^3+4xyz^2+2z^2y^2
16(2z-3)
(1) y2-2zy-2y-2z-3 = y2 -2y (z+1) - (2z+3) Delta = [-(z+1)]2 - (- (2z+3)) = z2+2z+1+2z+3= z2+2z+4 = (z+2)2 (If used the reduced form as b=-2(z+1) is even, b'=-(z+1) and delta=b'2-ac) y=(z+1) ± (z+2) so y = 2z+3 or y =-1 So the (1) can be written (y-2z-3)(y+1)
2z+9.75-7z=-5.15
2(z-2)(z-5)