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Let its sides be a b c and their opposite angles be A B C and so:-

Using the cosine rule angle A = 17.9 degrees

Using the cosine rule angle B = 120 degrees

Angle C: 180 -17.9 -120 = 42.1 degrees

Area: 0.5*48*22*sin(120) = 457 square cm rounded

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7y ago
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7y ago

The area is 457.3 cm^2 and the angles are: A = 17.9 deg, B = 120.0 deg and C = 42.1 deg.

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Q: What is the area and its angles of a triangle with sides of 22 cm by 62 cm by 48 cm?
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