3
Point: (-6, -2) Slope: 5 Equation: y = 5x+28
If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90
Slope: 5 Points: (-2, -3) Equation: y = 5x+7
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
Point: (2, -1) Slope: -5 Equation: y = -5x+9
To determine if the point (5, 6) is on the graph of the equation ( y - 2x + 5 = 0 ), we can substitute ( x = 5 ) into the equation. This gives us ( y - 2(5) + 5 = 0 ) or ( y - 10 + 5 = 0 ), which simplifies to ( y = 5 ). Since the point has coordinates (5, 6), and our calculation gives us ( y = 5 ), the point (5, 6) is not on the graph of the equation.
The equation of a circle can be expressed in the standard form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. For a circle centered at the point ((-2, 5)) with a radius of (2), the equation becomes ((x + 2)^2 + (y - 5)^2 = 2^2). Simplifying this gives ((x + 2)^2 + (y - 5)^2 = 4).
Equation of circle: (x-3)^2 +(y-2)^2 = 8
(6,2)
5
(x + 2)2 + (y - 5)2 = 4