Q: What is the length of a line segment that joins (11) and (3-3)?

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24

First find the points where the straight line meets with the curve: x2+2x-7 = 17-3x x2+2x+3x-7-17 = 0 x2+5x-24 = 0 Solving the above by means of the quadratic equation formula gives x values of -8 and 3 when x = 3, y = 8 and when x = -8, y = 41 (x2-x1)2+(y2-y1)2 = (line length)2 (-8-3)2+(41-8)2 = 1210 and its square root is the length of the line Length = 11 times the square root of 10 which is about 34.785 units of length

-1.5 :]

Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)

Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)

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4 11 10.8

Points: (-11, 0) and (9, -1) Midpoint: (-1, -1/2)

Fatty Joins the Force was created on 1913-11-24.

11

B is (-5, 9).

First find the points where the straight line meets with the curve: x2+2x-7 = 17-3x x2+2x+3x-7-17 = 0 x2+5x-24 = 0 Solving the above by means of the quadratic equation formula gives x values of -8 and 3 when x = 3, y = 8 and when x = -8, y = 41 (x2-x1)2+(y2-y1)2 = (line length)2 (-8-3)2+(41-8)2 = 1210 and its square root is the length of the line Length = 11 times the square root of 10 which is about 34.785 units of length

Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)

Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)

-1.5 :]