<ab> = |a|*|b|*cos(x) where |a| is the length of the vector a, |b| is the length of the vector b, and x is the angle between them.
Area of Triangle= 1/2(ab) You must multiply length b and length a together and then half it.
b*ab = ab2 Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then ab2 = ab + b2 b = 1 + b/a would have to be true for all b. Counter-example: b = 2; a = 3 b(ab) = 2(3)(2) = 12 = ab2 = (4)(3) ab + b2 = (2)(3) + (2) = 10 but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2
No, A+B is left as A+B AB would be A x B
Let y= ab+(- a)(b) +(-a)(-b) factor out -a y= ab+(-a){b+(-b)} y=ab+(-a)(0) y =ab -------------------(1) now factor out b y= b{a+(-a)}+(-a)(-b) y= b(0) +(-a)(-b) y= (-a)(-b)-----------------(2) equate (1) and (2) (-a)(-b)=ab minus x minus = positive
Length AB is 17 units
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
If you mean endpoints of (-1, -3) and (11, -8) then the length works out as 13
Using the distance formula the length of ab is 5 units
Using the distance formula the length of ab is 5 units
6.71
<ab> = |a|*|b|*cos(x) where |a| is the length of the vector a, |b| is the length of the vector b, and x is the angle between them.
If you mean endpoints (-1, -3) and (11, -8) then by using the distance formula the length between the points is 13 units
The length is 3*sqrt(5) = 6.7082, approx.
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End points: (-2, -4) and (-8, 4) Length of line AB: 10