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To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows:
[ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ]
Therefore, the length of AB is approximately 16.28 units.
What else can I help you with?
How do you find the dot product ab of two vectors if you know their lengths and the angle between them?
<ab> = |a|*|b|*cos(x) where |a| is the length of the vector a, |b| is the length of the vector b, and x is the angle between them.
Is A(-1-3) and B(11-8) what is the length of ab?
To find the length of segment AB between points A(-1, -3) and B(11, -8), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have: [ d = \sqrt{(11 - (-1))^2 + (-8 - (-3))^2} = \sqrt{(12)^2 + (-5)^2} = \sqrt{144 + 25} = \sqrt{169} = 13. ] Thus, the length of AB is 13 units.
If a(9 18) and B(1 12) what is the length of AB?
To find the length of segment AB between points A(9, 18) and B(1, 12), you can use the distance formula: [ AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting in the coordinates, we get: [ AB = \sqrt{(1 - 9)^2 + (12 - 18)^2} = \sqrt{(-8)^2 + (-6)^2} = \sqrt{64 + 36} = \sqrt{100} = 10. ] Thus, the length of AB is 10 units.
What is the the formula for finding the area of a triangle?
Area of Triangle= 1/2(ab) You must multiply length b and length a together and then half it.
If A (0 0) and B (6 3) what is the length of AB?
To find the length of the line segment AB, you can use the distance formula: ( AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). For points A(0, 0) and B(6, 3), the calculation is ( AB = \sqrt{(6 - 0)^2 + (3 - 0)^2} = \sqrt{6^2 + 3^2} = \sqrt{36 + 9} = \sqrt{45} = 3\sqrt{5} ). Therefore, the length of AB is ( 3\sqrt{5} ).
If A(79) and B(312) what is the length of--ab?
To find the length of the difference between A(79) and B(312), you subtract the two values: ( ab = B - A = 312 - 79 = 233 ). Therefore, the length of ( ab ) is 233.
If A (10 4) and B (2 19) what is the length of AB?
Length AB is 17 units
If a (0 0) and b (8 2) what is the length of ab?
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
If A is the point -2 -4 and B is -8 4 what is the length of AB?
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
If a equals negative 1 -3 and b equals 11 -8 what is the length of AB?
If you mean endpoints of (-1, -3) and (11, -8) then the length works out as 13
If a (7 9) and b (3 12) what is the length of ab?
Using the distance formula the length of ab is 5 units
If A (-2 -4) and B (-8 4) what is the length of Ab?
Using the distance formula the length of ab is 5 units
if a=(0,0) and b=(6,3) what is the length of ab?
6.71
How do you find the dot product ab of two vectors if you know their lengths and the angle between them?
<ab> = |a|*|b|*cos(x) where |a| is the length of the vector a, |b| is the length of the vector b, and x is the angle between them.
If a(-1-3)and b(11-8)what is the length of ab?
If you mean endpoints (-1, -3) and (11, -8) then by using the distance formula the length between the points is 13 units
Is A(-1-3) and B(11-8) what is the length of ab?
To find the length of segment AB between points A(-1, -3) and B(11, -8), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have: [ d = \sqrt{(11 - (-1))^2 + (-8 - (-3))^2} = \sqrt{(12)^2 + (-5)^2} = \sqrt{144 + 25} = \sqrt{169} = 13. ] Thus, the length of AB is 13 units.
If A (00) and B (63) what is the length of ab?
The length is 3*sqrt(5) = 6.7082, approx.
