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The length of the blue line segment is 11 and the length of the red line segment is 19 How long is the major axis of the ellipse?
24
How long is the blue line segment The length of the transverse axis is 11 and the length of the red line segment is 19.?
To determine the length of the blue line segment, we need to understand the context of the transverse axis and the red line segment. If the red line segment represents the length of the major axis of an ellipse, and the transverse axis is the distance across the ellipse at its widest point, then the blue line segment could be half the length of the transverse axis. However, without additional information about the relationship between these segments, a precise length for the blue line segment cannot be determined.
Find the length of the line segment with end points (72) and (-42) and explain?
To find the length of the line segment with endpoints (7, 2) and (-4, 2), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have (d = \sqrt{((-4) - 7)^2 + (2 - 2)^2} = \sqrt{(-11)^2 + 0^2} = \sqrt{121} = 11). Thus, the length of the line segment is 11 units.
If a -1-3 and b 11-8 what is the length of AB?
To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
How do you find the length of the straight line y equals 17 -3x that joins the curve y equals x squared plus 2x -7?
First find the points where the straight line meets with the curve: x2+2x-7 = 17-3x x2+2x+3x-7-17 = 0 x2+5x-24 = 0 Solving the above by means of the quadratic equation formula gives x values of -8 and 3 when x = 3, y = 8 and when x = -8, y = 41 (x2-x1)2+(y2-y1)2 = (line length)2 (-8-3)2+(41-8)2 = 1210 and its square root is the length of the line Length = 11 times the square root of 10 which is about 34.785 units of length
The length of the transverse axis is 11 and the length of the red line segment is 19 How long is the blue line segment?
8
The length of the blue line segment is 11 and the length of the red line segment is 13 How long is the major axis of the ellipse?
24
The length of the blue line segment is 11 and the length of the red line segment is 19 How long is the major axis of the ellipse?
24
The length of the red line segment is 8 and the length of the blue line segment is 3 How long is the major axis of the ellipse?
4 11 10.8
How long is the blue line segment The length of the transverse axis is 11 and the length of the red line segment is 19.?
To determine the length of the blue line segment, we need to understand the context of the transverse axis and the red line segment. If the red line segment represents the length of the major axis of an ellipse, and the transverse axis is the distance across the ellipse at its widest point, then the blue line segment could be half the length of the transverse axis. However, without additional information about the relationship between these segments, a precise length for the blue line segment cannot be determined.
Find the length of the line segment with end points (72) and (-42) and explain?
To find the length of the line segment with endpoints (7, 2) and (-4, 2), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have (d = \sqrt{((-4) - 7)^2 + (2 - 2)^2} = \sqrt{(-11)^2 + 0^2} = \sqrt{121} = 11). Thus, the length of the line segment is 11 units.
What is the midpoint of the line segment with endpoints -11 0 and 9 -1?
Points: (-11, 0) and (9, -1) Midpoint: (-1, -1/2)
When was Fatty Joins the Force created?
Fatty Joins the Force was created on 1913-11-24.
Which numbers 1-10 have straight line segments?
11
M is the midpoint of line segment AB. A has coordinates (3-7) and M has coordinates (-11). What is the coordinates of B?
B is (-5, 9).
If a -1-3 and b 11-8 what is the length of AB?
To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
How do you find the length of the straight line y equals 17 -3x that joins the curve y equals x squared plus 2x -7?
First find the points where the straight line meets with the curve: x2+2x-7 = 17-3x x2+2x+3x-7-17 = 0 x2+5x-24 = 0 Solving the above by means of the quadratic equation formula gives x values of -8 and 3 when x = 3, y = 8 and when x = -8, y = 41 (x2-x1)2+(y2-y1)2 = (line length)2 (-8-3)2+(41-8)2 = 1210 and its square root is the length of the line Length = 11 times the square root of 10 which is about 34.785 units of length
