Not enough information is given to class it as a straight line equation inasmuch as there is no equality sign and the plus or minus values are missing.
If you mean: y = 4x+5 then the perpendicular slope is -1/4
4x+y = 14 will be parallel to the above equation because the slope or gradient remains the same but the y intercept changes.
The straight line equation is: y = -4x+1
The equation, y = -4x - 3, is written in what's called slope-intercept form. The general equation for slope-intercept form is y = mx + b, where m is the slope of the line, and b is the y-intercept. So, for the equation in question, m = -4 and b = -3. Thus, the slope of the line is -4.
I assume you mean y = 4x If so, then it is 4.
what is the slope of the line that has the equation 4x+2y=12?
Slope = 4
If the equation is x+4 the slope is 1. If the equation is 4x than the slope is 4.
If you mean: y = 4x+5 then the perpendicular slope is -1/4
The slope is -4
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
4x+y = 14 will be parallel to the above equation because the slope or gradient remains the same but the y intercept changes.
The straight line equation is: y = -4x+1
The equation, y = -4x - 3, is written in what's called slope-intercept form. The general equation for slope-intercept form is y = mx + b, where m is the slope of the line, and b is the y-intercept. So, for the equation in question, m = -4 and b = -3. Thus, the slope of the line is -4.
I assume you mean y = 4x If so, then it is 4.
If you mean y = 4x-1 then the slope is 4 and the y intercept is -1
There is a standard equation for a straight line. It is y = mx + b. m is the slope and b is the y-intercept (when x = 0). In the question m = -4 and is therefore the slope of the line represented by the equation y = -4x + 7.