Using Pythagoras' theorem it is 8 Times Square root of 58 which is about 61 feet
The diagonal is about 28.3 feet.
To find the diagonal of a rectangle with dimensions 24 feet by 36 feet, you can use the Pythagorean theorem. The diagonal (d) can be calculated using the formula (d = \sqrt{(length^2 + width^2)}). Plugging in the values: (d = \sqrt{(24^2 + 36^2)} = \sqrt{(576 + 1296)} = \sqrt{1872} \approx 43.27) feet. Therefore, the diagonal is approximately 43.27 feet long.
24 feet.
The perimeter of a 5 by 7 rectangle is 24.
24 feet square feet
Diagonal = 36.9 feet
36.8782 ft
46.648 ft
The diagonal of a 12' x 24' rectangle is approx 26.8'.
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
The diagonal is approximately 38.42 feet.
The diagonal is about 28.3 feet.
Well, isn't that a happy little question! To find the diagonal measurement of a square, we can use the Pythagorean theorem. So, for a square that is 16 feet by 24 feet, we can calculate the diagonal by taking the square root of (16^2 + 24^2), which equals about 28.84 feet. Just imagine that diagonal stretching across your square canvas, creating a beautiful harmony of length and width.
Ah, what a lovely question! To find the diagonal measurement of a square, we can use the Pythagorean theorem. So, for a square that is 24 feet by 24 feet, we can use the formula diagonal = √(side length squared + side length squared). Plugging in the values, we get diagonal = √(24^2 + 24^2) = √(576 + 576) = √1152 ≈ 33.94 feet.
Oh, dude, you're hitting me with the math questions now? Okay, okay, let me think. So, the diagonal of a rectangle can be found using the Pythagorean theorem, right? So, it's like the square root of (24 squared + 30 squared). That's like 36 feet. So, the diagonal of a 24 ft by 30 ft rectangle is 36 feet.
Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet
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