If x = -7, then x3 = -343 so that 2x3 = -686 y = 2 then 15 y = 30 So 2x3 + 15y = -686 + 30 = -656
Either the answer is the point in the second quadrant, at a distance of one unit from each of the coordinate axes, or the question is incomplete.
y=0 is a horizontal line on the x-axis. Therefore, it does not lie in any quadrant.
y=6x is in the third quadrant while x is negative and in the first quadrant while x is positive.
Slope for the equation y equals 7 is zero.
it lies in the 2nd and 4th quadrants
If x = -7, then x3 = -343 so that 2x3 = -686 y = 2 then 15 y = 30 So 2x3 + 15y = -686 + 30 = -656
Either the answer is the point in the second quadrant, at a distance of one unit from each of the coordinate axes, or the question is incomplete.
y=0 is a horizontal line on the x-axis. Therefore, it does not lie in any quadrant.
y=6x is in the third quadrant while x is negative and in the first quadrant while x is positive.
Slope for the equation y equals 7 is zero.
Third and fourth
No. [ y = 4x2 ] is a quadratic equation.
x = -7, y = 2 ⇒ 2x3 + 15y = 2 x (-7)3 + 15 x 2 = 2 x (-343) + 15 x 2 = -656
At what point does line represented by the equation 8x + 4y = -4 intersects the y-axis, and at what point in the negative direction of x-axis.
x = 0 and y = 4
x = 2 and y = -4