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Ted Haley

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12y ago

802/10 = 80 remainder 2

8002/100 = 80 remainder 2

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Q: What two division problems you get 80 as a dividend and 2 as a remainder?
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What two division problems you get 80 as a dividend ans 2 as a remainder?

40


How do we find remainder of two numbers by using addition subtraction multiplication and division?

The remainder of two positive integers can be calculated by first dividing one number (the dividend) by the other (the divisor) using integer division (ignoring any fractional component). Multiply this quotient by the divisor, then subtract the product from the dividend. The result is the remainder. Alternatively, while the dividend remains greater than the divisor, subtract the divisor from the dividend and repeat until the dividend is smaller than the divisor. The dividend is then the remainder.


How do you solve a long division problem?

How to solve long division problem:When dividing two numbers, the dividend and divisor; the answer is the quotient.Make note of where decimal points is in the dividend and divisor.Simplify the long division problem by moving the decimals of the divisor and dividend by the same number of decimal places.Keep the numbers lined up straight from top to bottom.After each step, be sure the remainder for that step is less than the divisor. If it is not, there is a problem - check your math.In the end, any left over is called the remainder


How do you find a negative remainder of a number?

This is a common operation in Number Theory, especially in relation to Euclid's Algorism.If, when dividing two numbers, complete division does not occur then usually the operation stops at a value less than the dividend and the resulting difference is described as the remainder.Example : 88 ÷ 7 = 12 with remainder 4. (12 x 7 = 84)A negative remainder is when the division stops at a value greater than the dividend. Normally this is the value immediately greater than the dividend.Example : 88 ÷ 7 = 13 with remainder -3 (13 x 7 = 91)


How do you find a missing dividend in a division problem?

The three parts to a division problem are: Dividend, Divisor, and Qoutient. To calculate the value of any of the terms, two of the terms need to be known values. To calculate the dividend, multiply the quotient by the divisor.

Related questions

What two division problems you get 80 as a dividend ans 2 as a remainder?

40


How do we find remainder of two numbers by using addition subtraction multiplication and division?

The remainder of two positive integers can be calculated by first dividing one number (the dividend) by the other (the divisor) using integer division (ignoring any fractional component). Multiply this quotient by the divisor, then subtract the product from the dividend. The result is the remainder. Alternatively, while the dividend remains greater than the divisor, subtract the divisor from the dividend and repeat until the dividend is smaller than the divisor. The dividend is then the remainder.


How do you divide two numbers without division operator?

int dividend,divisor,remainder; int division(int p,int q){ int quotient=1; /*if divisor and diviend are equal then quotient=1*/ if(p==q){ remainder=0; return 1; } /*if dividend is smaller than divisor then remainder=dividend*/ if(p<q){ remainder=p; return 0; } /*shift left till divisor > dividend*/ while(p>=q){ q<<=1; quotient<<=1; } /*shift right for one time so that divisor become smaller than dividend*/ q>>=1; quotient>>=1; /*again call division recurcively*/ quotient+=division(p-q,divisor); return quotient; } int main(){ cout<<"\nEnter dividend:"; cin>>dividend; cout<<"\nEnter divisor:"; cin>>divisor; cout<<"\nQuotient:"<<division(dividend,divisor); cout<<"\nRemainder:"<<remainder; //system("pause"); return 0; }


Where is the dividend located in a division problem?

In any two-figure division sum, the format is: dividend / divisor = quotient


How do you solve a long division problem?

How to solve long division problem:When dividing two numbers, the dividend and divisor; the answer is the quotient.Make note of where decimal points is in the dividend and divisor.Simplify the long division problem by moving the decimals of the divisor and dividend by the same number of decimal places.Keep the numbers lined up straight from top to bottom.After each step, be sure the remainder for that step is less than the divisor. If it is not, there is a problem - check your math.In the end, any left over is called the remainder


How do you find a negative remainder of a number?

This is a common operation in Number Theory, especially in relation to Euclid's Algorism.If, when dividing two numbers, complete division does not occur then usually the operation stops at a value less than the dividend and the resulting difference is described as the remainder.Example : 88 ÷ 7 = 12 with remainder 4. (12 x 7 = 84)A negative remainder is when the division stops at a value greater than the dividend. Normally this is the value immediately greater than the dividend.Example : 88 ÷ 7 = 13 with remainder -3 (13 x 7 = 91)


If you add two zeros to the divisor but you still have a remainder what do you do?

If you add two zeroes to the divisor but still have a remainder, add zeroes to the dividend. Adding zeroes to the divisor will not help.


How do you find a missing dividend in a division problem?

The three parts to a division problem are: Dividend, Divisor, and Qoutient. To calculate the value of any of the terms, two of the terms need to be known values. To calculate the dividend, multiply the quotient by the divisor.


How many different division problems can you solve with the 1010 multiplicaiton table if you do not include problems with a dividend of 0?

Undefined: You cannot divide by zero


What is the product called when you divide two numbers?

The answer is a product for any math question. Specifically for division I think it is a dividend.


What is the left number called?

It is the remainder when you perform division with any two numbers in mathematics.


How do you make up your own division problem?

Get two numbers and put a division sign in between them.