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What else can I help you with?
What is the amplitude for y equals sin x divided by 2?
Assuming the question refers to [sin(x)]/2 rather than sin(x/2) the answer is 1.
What is the amplitude of y equals sin x?
The amplitude is 1.
Determine the amplitude of y equals -4 sin x?
The amplitude is 4 .
What is the amplitude for y equals 5 sin x?
5
How do you determine that the amplitude of y equals -2 sin x?
The amplitude of a function is half the distance between the maximum and minimum values. This is the absolute value of the number in front of the trig function. for example, y=Asin(x) or y= Acos(x) the absolute value of A is the amplitude. Therefore, the amplitude of y=-2sinx is 2
Determine the amplitude of y equals -2 sin x?
The amplitude of the wave [ y = -2 sin(x) ] is 2.
Find the amplitude and period of the functions and sketch their graphs y equals sin -x?
y = sin(-x)Amplitude = 1Period = 2 pi
What is the amplitude for y equals sin x divided by 2?
Assuming the question refers to [sin(x)]/2 rather than sin(x/2) the answer is 1.
What is the amplitude of y equals sin x?
The amplitude is 1.
Determine the amplitude of y equals -4 sin x?
The amplitude is 4 .
What is the amplitude for y equals 5 sin x?
5
Determine the amplitude of y-2 sin x?
The amplitude is |-2| = 2.
What is the amplitude for the function y equals 6sinx?
The amplitude of the function [ sin(x) ] is 1 peak and 2 peak-to-peak . The amplitude of 6 times that function is 6 peak and 12 peak-to-peak.
How do you determine that the amplitude of y equals -2 sin x?
The amplitude of a function is half the distance between the maximum and minimum values. This is the absolute value of the number in front of the trig function. for example, y=Asin(x) or y= Acos(x) the absolute value of A is the amplitude. Therefore, the amplitude of y=-2sinx is 2
2 sin x - 3 equals 0?
2 sin(x) - 3 = 0 2 sin(x) = 3 sin(x) = 1.5 No solution. The maximum value of the sine function is 1.0 .
Need help with working this Trig problem out. A sin alpha plus cos alpha equals 1 B sin alpha - cos alpha equals 1 Solution is AB equals 1?
A*sin(x) + cos(x) = 1B*sin(x) - cos(x) = 1Add the two equations: A*sin(x) + B*sin(x) = 2(A+B)*sin(x) = 2sin(x) = 2/(A+B)x = arcsin{2/(A+B)}That is the main solution. There may be others: depending on the range for x.
How do you show that 2 sin squared x minus 1 divided by sin x minus cos x equals sin x plus cos x?
(2 sin^2 x - 1)/(sin x - cos x) = sin x + cos x (sin^2 x + sin^2 x - 1)/(sin x - cos x) =? sin x + cos x [sin^2 x - (1 - sin^2 x)]/(sin x - cos x) =? sin x + cos x (sin^2 x - cos^2 x)/(sin x - cos x) =? sin x + cos x [(sin x - cos x)(sin x + cos x)]/(sin x - cos x) =? sin x + cos x sin x + cos x = sin x + cos x
