This is a binomial probability distribution with the following criteria: Number of trials = 6, number of successes = 2, probability of success = 1/6 or 0.16667. Because of the probability value not being a typical number, there is not a table to go to look the answer up. The math is tedious. So, we go to a binomial probability calculator and enter in the aforementioned data to obtain the answer of 0.201.
2/4
There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.
50%
0.1%
0.25 binomial distribution, where p=0.5, q=0.5, x=3, n=4 4!/(3!*1!)*0.530.51 = 0.25 Also can be solved by identifying each event possible and related probability. There are 4 ways this can occur (first child is a girl, second child is a girl, third child is a girl and fourth child is a girl) and there is a 0.54 chance of each of these events occurring. Prob= 4 *0.0625 = 0.25
The probability is 2 - 6
2/4
Start with examples like flipping a coin, rolling a die or spinning a dreidel. Then explain in terms they understand. That depends very much on the age of the child.
This is a Binomial Probability; p=0.5, n=10 & x=7. Since you want the probability of exactly 7, in the related link calculator, after placing in the above values, P(x=7) = 0.1172 or 11.72%.
No probability. Neither parent has an "A" for the child to inherit to make an "AB".
There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.
1 in 2
The probability is zero! There is no such thing as "normal". Every child (and adult) has some unique characteristics and that makes them not normal - in that respect.
It depends on the context: if you select a child at random from a girls' school, the probability is 0, while if it is at a boys' school it is 1!
The addition rule is used when calculating the probability of two mutually exclusive events occurring together. For example, when calculating the probability of rolling a 2 or a 6 on a six-sided die, you would use the addition rule.
50%
50%