252 combinations, :)
12,108,327
There are 8,592,039,666 combinations of 6 numbers out of 138 numbers, like the numbers from 1 to 138.
(35!)/(29! 6!) = (35 x 34 x 33 x 32 x 31 x 30)/(6 x 5 x 4 x 3 x 2) = 1,623,160
The sum you require is 4!/2!2!, which is 6. This means there are 6 different two-digit numbers. * * * * * Wrong! The above formula is for the number of combinations, not permutations. However, since the number 23 is different from the number 32, you require permutations and not combinations. There are 4*3 = 12 23, 25, 27, 32, 35, 37, 52, 53, 57, 72, 73, 75.
252 combinations, :)
There are 6C3 = 20 such combinations.
The number of combinations of 6 letters is 6! or 720.
Number of combinations = 45C6 = 45!/6!(45-6)! = 8,145,060
There are 33C6 = 33*32*31*30*29*28/(6*5*4*3*2*1) = 1,107,568 combinations.
12,108,327
There are 8145060 combinations.
There are 8,592,039,666 combinations of 6 numbers out of 138 numbers, like the numbers from 1 to 138.
just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436
654321-100000= 554321 combinations
There are 15 combinations.
6 of them.