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You need a formula for this.

If the probability (in one toss) of getting head is "p", then the probability of getting exactly k heads out of n tosses is:

(n,k) p^k (1-p)^(n-k)

where (n,k) denotes the number of combinations of k elements among n.

You should also know that (n,k) = n! / (( n-k)! k! )

so here, with n=8, k=6, and p=.5 you have

(n,k) = 8*7 / 2 = 28

and your probability is :

28 * 1/2^6 * 1/2^2 = 28 / 256 = 7 / 64

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12y ago

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