The probability is (4/52) * (4/52) = 1/169 = 0.0059, approx.
There are two one-eye jacks in a standard deck of 52 cards. So the probability of getting one is 2/52 = 1/26
The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256
It is approx 0.1445
It is 0.375
0.0769
The probability is (4/52) * (4/52) = 1/169 = 0.0059, approx.
Probability that it is one of these eight cards is 8/52. Hence the probability of not getting these eight cards is 44/52
The probability of getting exactly seven tails if you flip a coin eight times is: P(7T1H) = 8∙(1/2)8 =0.03125 ≈ 3.1%
There are two one-eye jacks in a standard deck of 52 cards. So the probability of getting one is 2/52 = 1/26
The probability of getting exactly eight heads when tossing 10 coins once can be found using the binomial probability formula. Assuming a fair coin, the probability of getting a heads is 1/2. Plugging in the numbers, the probability of getting exactly eight heads is (10 choose 8) * (1/2)^8 * (1/2)^2 = 45/1024, which is approximately 0.04395.
The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256
It is approx 0.1445
It is 93/256 = 0.363 approx.
It is 0.375
00
1/26