9
The ways to get a sum of six or fewer are listed below, along with the number of ways you can get each one. The probability of each way is the same: one sixth to the third power, or one 216th.
111: 1
112: 3
113: 3
114: 3
122: 3
123: 6
222: 1
The total number of ways to get a sum of six or less is 20. Each has a 1/216 chance, so the total probability is 20/216 = 5/54. We want the probability of getting greater than six, so we subtract this from one. 1 - 5/54 = 49/54 = 0.907.
The probability of getting an even number on at least one of the 3 rolls is 7/8.
5-6
There are 30 possible combinations of die rolls (assuming 2 6-sided die) (excluding "doubles") The highest total you can get is 12 so the numbers you are after are 10,11 and 12... The possible combos which add to greater than 9 are: 4,6 6,4 5,5 5,6 6,5 So the probability of rolling a 10, 11 or 12 is 5:30 (5 times out of 30 rolls)
The answer depends on how often you roll it! For one roll it is 1/6 but the probability increases to a near certainty as you increase the number of rolls.
Probability is the likelihood that something will occur. If you subtract it from 1, we get the likelihood (or probability) that it will not occur. If a coin is tossed and rolls heads 6 times, the (empirical) probability of obtaining a head is 6/10 or .6. 1-.6 =.4 is the empirical probability (or likelihood) of not getting a head.
The probability of 3 specific dice rolls is the probability that each one will happen multiplied together. For instance, the probability of rolling 2 then 6 then 4 is the probability of all of these multiplied together: The probability of rolling 2 is 1/6. The probability of rolling 6 is 1/6. The probability of rolling 4 is 1/6. Multiply these together and we get the total probability as 1/216
The probability of getting an even number on at least one of the 3 rolls is 7/8.
5-6
There are 30 possible combinations of die rolls (assuming 2 6-sided die) (excluding "doubles") The highest total you can get is 12 so the numbers you are after are 10,11 and 12... The possible combos which add to greater than 9 are: 4,6 6,4 5,5 5,6 6,5 So the probability of rolling a 10, 11 or 12 is 5:30 (5 times out of 30 rolls)
The answer depends on how often you roll it! For one roll it is 1/6 but the probability increases to a near certainty as you increase the number of rolls.
What is the probability of 1, 6, 4, on 3 rolls of a die
The probability that each roll will be a 1, is 1/6 (a sixth) because there is one outcome of interest (getting a 1) and 6 possible outcomes (6 numbers on the die).Probability rules mean that if you want the probability of getting outcome A and getting outcome B then the total probability is P(A) x P(B) where P(A) means the probability of getting outcome A).In short if you want P(A and B) then this is P(A) x P(B)Applied to this example if you want the probability of getting a 1 on each throw of the die (i.e. on all 3 throws) then the probability is given by:P(1 on all three rolls) = P(1 on first roll) x P(1 on second role) x P(1 on third role)P(1 on all three rolls) = 1/6 x 1/6 x 1/6P(1 on all three rolls) = 1 / 216
The probability of rolling a 2 is 1 in 6. The probability of rolling an even number is 3 in 6. The probability of doing both, on two rolls, is 3 in 36, or 1 in 12.
Probability is the likelihood that something will occur. If you subtract it from 1, we get the likelihood (or probability) that it will not occur. If a coin is tossed and rolls heads 6 times, the (empirical) probability of obtaining a head is 6/10 or .6. 1-.6 =.4 is the empirical probability (or likelihood) of not getting a head.
Anywhere from 0 to 1; it depends on the shape and what numbers are written on the faces.
The probability of not rolling it ever is 0.For n rolls it is (5/6)n sofor 10 rolls it is 0.1615for 20 rolls it is 2.608*10-2for 100 rolls it is 1.207*10-8 and so on.
Total number of possible rolls with 2 dice = 36.Total number of rolls that are doubles = 6.Probability of rolling doubles= 6/36 = 1/6 = (16 and 2/3) percent .