9
5-6
There are 30 possible combinations of die rolls (assuming 2 6-sided die) (excluding "doubles") The highest total you can get is 12 so the numbers you are after are 10,11 and 12... The possible combos which add to greater than 9 are: 4,6 6,4 5,5 5,6 6,5 So the probability of rolling a 10, 11 or 12 is 5:30 (5 times out of 30 rolls)
The answer depends on how often you roll it! For one roll it is 1/6 but the probability increases to a near certainty as you increase the number of rolls.
if a die is rolled.What is the probibil ty that an even number divisible by 3 appears
Probability is the likelihood that something will occur. If you subtract it from 1, we get the likelihood (or probability) that it will not occur. If a coin is tossed and rolls heads 6 times, the (empirical) probability of obtaining a head is 6/10 or .6. 1-.6 =.4 is the empirical probability (or likelihood) of not getting a head.
The probability of 3 specific dice rolls is the probability that each one will happen multiplied together. For instance, the probability of rolling 2 then 6 then 4 is the probability of all of these multiplied together: The probability of rolling 2 is 1/6. The probability of rolling 6 is 1/6. The probability of rolling 4 is 1/6. Multiply these together and we get the total probability as 1/216
5-6
There are 30 possible combinations of die rolls (assuming 2 6-sided die) (excluding "doubles") The highest total you can get is 12 so the numbers you are after are 10,11 and 12... The possible combos which add to greater than 9 are: 4,6 6,4 5,5 5,6 6,5 So the probability of rolling a 10, 11 or 12 is 5:30 (5 times out of 30 rolls)
The answer depends on how often you roll it! For one roll it is 1/6 but the probability increases to a near certainty as you increase the number of rolls.
What is the probability of 1, 6, 4, on 3 rolls of a die
The probability that each roll will be a 1, is 1/6 (a sixth) because there is one outcome of interest (getting a 1) and 6 possible outcomes (6 numbers on the die).Probability rules mean that if you want the probability of getting outcome A and getting outcome B then the total probability is P(A) x P(B) where P(A) means the probability of getting outcome A).In short if you want P(A and B) then this is P(A) x P(B)Applied to this example if you want the probability of getting a 1 on each throw of the die (i.e. on all 3 throws) then the probability is given by:P(1 on all three rolls) = P(1 on first roll) x P(1 on second role) x P(1 on third role)P(1 on all three rolls) = 1/6 x 1/6 x 1/6P(1 on all three rolls) = 1 / 216
if a die is rolled.What is the probibil ty that an even number divisible by 3 appears
The probability of rolling a 2 is 1 in 6. The probability of rolling an even number is 3 in 6. The probability of doing both, on two rolls, is 3 in 36, or 1 in 12.
Probability is the likelihood that something will occur. If you subtract it from 1, we get the likelihood (or probability) that it will not occur. If a coin is tossed and rolls heads 6 times, the (empirical) probability of obtaining a head is 6/10 or .6. 1-.6 =.4 is the empirical probability (or likelihood) of not getting a head.
Anywhere from 0 to 1; it depends on the shape and what numbers are written on the faces.
The probability of not rolling it ever is 0.For n rolls it is (5/6)n sofor 10 rolls it is 0.1615for 20 rolls it is 2.608*10-2for 100 rolls it is 1.207*10-8 and so on.
With a fair die, it is 1/216 in three rolls, but the probability increases to 1 (a certainty) as the number of rolls is increased.