5 + 10+15+20=50 ans
To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
The common multiples of 5 and 6 are the multiples of their lowest common multiple (which is 30), so there are infinitely many common multiples of 5 and 6. The first five are: 30, 60, 90, 120, 150.
6, 12, 18, 24, 30
The first five nonzero multiples of 6 are 6, 12, 18, 24 and 30.
90
5 + 10+15+20=50 ans
It is: 6+12+18 = 36
Multiples of 6 are numbers in the 6 times table. So the first 5 multiples of 6 are 6, 12, 18, 24 and 30.
To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
The first five multiples of 6 are 6, 12, 18, 24 and 30. For them to be common, they need to be compared to another set of multiples.
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
0, 2, 4, 6, 8.0,2,4,6,8 are the first five multiples of 2
30,60,90,120,150
The common multiples of 5 and 6 are the multiples of their lowest common multiple (which is 30), so there are infinitely many common multiples of 5 and 6. The first five are: 30, 60, 90, 120, 150.