There are 48 possible outcomes and I have no intention of listing them all.
They are all of the form CCCD
where C = H or T, and D takes the numeric values from 1 to 6.
2*2*2*2 = 16
Two
The total number of outcomes is 2^5 = 32.
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
Each coin has two possible outcomes, either Heads or Tails. Then the number of outcomes when all 4 coins are tossed is, 2 x 2 x 2 x 2 = 16.
24 possible outcomes.
9
I believe there would be 11 possible outcomes!
8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.
Eight of them.
There are eight (8).
The possible outcomes areHH, HT, TH and TT.
2*2*2*2 = 16
Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.
Heads ( H ) Tails ( T ) HH , TT , HT , TH
Two
There are eight possible outcomes: HHH, HHT, HTT, HTH, THT, TTT, TTH, THH.