0
Well, isn't that a happy little question! The probability of picking 6 numbers correctly out of 40 in a lottery is quite small, but every number has a chance to be picked, just like every tree in a forest is unique and special. Remember, it's not about the odds, it's about enjoying the process and spreading positivity wherever you go.
Still curious? Ask our experts.
Chat with our AI personalities
Lao
Ross
EzraOh, isn't that a fun question! When you're picking 6 numbers out of 40 for a lottery, the probability of getting all 6 numbers correct is quite small, but it's not impossible. Each number you pick has a 1 in 40 chance of being correct, so if you multiply those probabilities together, you'll find the overall probability of winning. Just remember, it's not about the odds, it's about enjoying the process!
Assuming there are six numbers drawn out of the set from 1 to 49, without replacement:
There are 15 out of 49 of these numbers that are prime. So the probability would be
(15 - 9)! / (49 - 43)! = (15 * 14 * 13 * 12 * 11 * 10) / (49 * 48 * 47 * 46 * 45 * 44)
= (24325271111131) / (27335172111231471) = (5 * 13) / (8 * 3 * 7 * 23 * 47)
= 65 / 181608
Add your answer:
Earn +20 pts
What is the probability of getting 6 numbers in a lottery of 40 numbers?
Well, isn't that a happy little question! The probability of getting all 6 numbers correct in a lottery of 40 numbers is quite small, but remember, it's all about enjoying the process of playing and not just the outcome. Keep a positive mindset and have fun with it, my friend!
What is the probability you will bowl a strike on your next attempt if you bowled four strikes out of ten?
the probability is put into a fraction for you. 4/10 which is simplified to 2/5. 2/5=40% the probability you will bowl a strike is 40%.
Set of three numbers is 110. The median of the numbers is 40 and the range is 30. What are the numbers?
20, 40, 50
What is the probability of drawing 1 card from each suit?
The answer depends on how many cards are drawn. If 40 are drawn without replacement, from a normal deck, the probability is 1. If 3 are drawn the probability is 0!
The probability that an individual is left handed is 0.11 In a class of 40 students what is the probability of finding five left handers?
If the probability of a person being left handed is .11, then the probability of a person being right handed is .89 (1.00 - .11). In a class of 40 people, there are 40! (40 factorial) = 40 x 39 x 38 x .... x 3 x 2 x 1 possible Permutations of students. Within this number, there are many that will yield exactly 5 left handed people. 40-P-5 is the number of Permutations of 5 within a class of 40 (sorry, can't use the correct formating here!): = 40! / (40 - 5) ! = 40! / 35! = 40 x 39 x 38 x 37 x 36 Since we don't care about order..... we need to factor out the number of identical permutations. 40-C-5 = 40-P-5 / 5! So.... (40 x 39 x 38 x 37 x 36) / (5 x 4 x 3 x 2 x 1) = 658,008 Now, what is the probability of any one such combination? (.89 to the power 35) x (.11 to the power 5) = 0.000000273 So the probability of exactly 5 left handed people in the class is 658,008 x .000000273 = 17.9408137 %
