1 half or 1 over 2
Assuming the spinner has only a finite number of colours, the probability is 0. If there are n colours then on the (n+1)th spin the spinner cannot land on a different colour.
The probability that the spinner will land on six depends on how many numbers are on the spinner. If the spinner is only 1 through 6, then there is a 16.67% probability that the spinner will land on six with each spin.
The answer depends on the shape of the spinner.
You have a 1/9 chance of landing a 2 on the first spin and a 1/9 chance of landing 5 on the second, so the chances of landing on a 2 then a 5 should be (1/9)*(1/9) = 1/81
The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.
Assuming the spinner has only a finite number of colours, the probability is 0. If there are n colours then on the (n+1)th spin the spinner cannot land on a different colour.
2/3
The probability that the spinner will land on six depends on how many numbers are on the spinner. If the spinner is only 1 through 6, then there is a 16.67% probability that the spinner will land on six with each spin.
The probability of landing on black twice on a spinner with white, black, and striped sections is (1/3)^2 = 1/9. This is because there is a 1/3 chance of landing on black on each spin, and the spins are independent events.
The answer depends on the shape of the spinner.
You have a 1/9 chance of landing a 2 on the first spin and a 1/9 chance of landing 5 on the second, so the chances of landing on a 2 then a 5 should be (1/9)*(1/9) = 1/81
To calculate the probability of spinning the black region twice on a spinner, you first need to determine the total number of possible outcomes when spinning the spinner twice. Let's say the spinner has 8 equal sections, with 2 black regions. The total outcomes for spinning the spinner twice would be 8 x 8 = 64. The probability of landing on the black region twice would be 2/8 x 2/8 = 4/64 = 1/16. Therefore, the probability of landing on the black region twice is 1/16 or approximately 0.0625.
1/3
It is 0.5
The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.
depends on the numbers on the spinner. if 1 thru 10, 7/10
Leg spin will spin away from a right hander where off spin will go into a right hander.