There are infinitely many sets.
Consider the sets: {16}, {16, 16}, {16, 16, 16}, {16, 16, ... , 16} etc.
It is easy to see that the mean, i each case, will be 16.
Then, leaving aside the first set, add one to any number and subtract 1 from any number bigger than 1. The mean of this new set will also be 16. And you can keep going.
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16.5 is the median. A median is the middle number of a set of numbers in order. If there are an even amount of numbers, as in this case, it is the number half way between the two middle numbers, in this case 16 and 17.
√16 x √81 = 4 x 9 = 36
well if by between 8 and 8 you mean 8+8 then divide it by two to get......8.- Yep, you are absolutely right!! if there were 3 numbers in a data set then u would have to cross keep crossing out numbers from each side until you get a remainder of only one number. In some cases you will not get ONLY one number. So, you would have to:1) Add 8 + 82) You get 16. So divide 16 by two because there are only two numbers in the set.3) You get 8.4) The median of 8 and 8 is 8!
Any two numbers that when multiplied, equal 8^2 (64). So, 2 and 32 work. So do 1 and 64. And 4 and 16. And .5 and 128
To calculate the number of 4-number combinations possible with 16 numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 16 (the total number of numbers) and r = 4 (the number of numbers in each combination). Plugging these values into the formula, you would calculate 16C4 = 16! / 4!(16-4)! = 1820. Therefore, there are 1820 possible 4-number combinations with 16 numbers.